Base | Representation |
---|---|
bin | 10000001010110011100… |
… | …100101011101001111111 |
3 | 10221012222110120201010122 |
4 | 100022303210223221333 |
5 | 121201030230100111 |
6 | 2210234443325155 |
7 | 143163306501431 |
oct | 20126344535177 |
9 | 3835873521118 |
10 | 1111114300031 |
11 | 39924806811a |
12 | 15b411b207bb |
13 | 80a155b2278 |
14 | 3bac760c651 |
15 | 1dd815bbcdb |
hex | 102b392ba7f |
1111114300031 has 2 divisors, whose sum is σ = 1111114300032. Its totient is φ = 1111114300030.
The previous prime is 1111114300027. The next prime is 1111114300067. The reversal of 1111114300031 is 1300034111111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1111114300031 - 22 = 1111114300027 is a prime.
It is a super-2 number, since 2×11111143000312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1111114299982 and 1111114300009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111114302031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555557150015 + 555557150016.
It is an arithmetic number, because the mean of its divisors is an integer number (555557150016).
Almost surely, 21111114300031 is an apocalyptic number.
1111114300031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111114300031 is an equidigital number, since it uses as much as digits as its factorization.
1111114300031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1111114300031 its reverse (1300034111111), we get a palindrome (2411148411142).
The spelling of 1111114300031 in words is "one trillion, one hundred eleven billion, one hundred fourteen million, three hundred thousand, thirty-one".
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