Base | Representation |
---|---|
bin | 11001010000111001000111… |
… | …111101011000010011110011 |
3 | 112120102012112002211202102122 |
4 | 121100321013331120103303 |
5 | 104030424344333021321 |
6 | 1032152053035304455 |
7 | 32255402135112041 |
oct | 3120710775302363 |
9 | 476365462752378 |
10 | 111112011220211 |
11 | 32449380716761 |
12 | 105663038ab12b |
13 | 49cca8263c311 |
14 | 1d61bc8707391 |
15 | cca4298ed8ab |
hex | 650e47f584f3 |
111112011220211 has 2 divisors, whose sum is σ = 111112011220212. Its totient is φ = 111112011220210.
The previous prime is 111112011220207. The next prime is 111112011220213. The reversal of 111112011220211 is 112022110211111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111112011220211 - 22 = 111112011220207 is a prime.
Together with 111112011220213, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111112011220211.
It is not a weakly prime, because it can be changed into another prime (111112011220213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556005610105 + 55556005610106.
It is an arithmetic number, because the mean of its divisors is an integer number (55556005610106).
Almost surely, 2111112011220211 is an apocalyptic number.
111112011220211 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112011220211 is an equidigital number, since it uses as much as digits as its factorization.
111112011220211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 17.
Adding to 111112011220211 its reverse (112022110211111), we get a palindrome (223134121431322).
The spelling of 111112011220211 in words is "one hundred eleven trillion, one hundred twelve billion, eleven million, two hundred twenty thousand, two hundred eleven".
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