Base | Representation |
---|---|
bin | 11001010000111001001111… |
… | …000010111100111001010011 |
3 | 112120102012211101120120001122 |
4 | 121100321033002330321103 |
5 | 104030430120302340144 |
6 | 1032152112523552455 |
7 | 32255405110545326 |
oct | 3120711702747123 |
9 | 476365741516048 |
10 | 111112130121299 |
11 | 3244943184791a |
12 | 1056633768b72b |
13 | 49ccaa116cca8 |
14 | 1d61bda4187bd |
15 | cca4350887ee |
hex | 650e4f0bce53 |
111112130121299 has 2 divisors, whose sum is σ = 111112130121300. Its totient is φ = 111112130121298.
The previous prime is 111112130121233. The next prime is 111112130121323. The reversal of 111112130121299 is 992121031211111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111112130121299 is a prime.
It is not a weakly prime, because it can be changed into another prime (111112130111299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556065060649 + 55556065060650.
It is an arithmetic number, because the mean of its divisors is an integer number (55556065060650).
Almost surely, 2111112130121299 is an apocalyptic number.
111112130121299 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112130121299 is an equidigital number, since it uses as much as digits as its factorization.
111112130121299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 35.
The spelling of 111112130121299 in words is "one hundred eleven trillion, one hundred twelve billion, one hundred thirty million, one hundred twenty-one thousand, two hundred ninety-nine".
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