Base | Representation |
---|---|
bin | 11001010000111001001111… |
… | …000010111100111001101011 |
3 | 112120102012211101120120002112 |
4 | 121100321033002330321223 |
5 | 104030430120302340243 |
6 | 1032152112523552535 |
7 | 32255405110545362 |
oct | 3120711702747153 |
9 | 476365741516075 |
10 | 111112130121323 |
11 | 32449431847941 |
12 | 1056633768b74b |
13 | 49ccaa116ccc6 |
14 | 1d61bda4187d9 |
15 | cca435088818 |
hex | 650e4f0bce6b |
111112130121323 has 2 divisors, whose sum is σ = 111112130121324. Its totient is φ = 111112130121322.
The previous prime is 111112130121299. The next prime is 111112130121389. The reversal of 111112130121323 is 323121031211111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111112130121323 - 28 = 111112130121067 is a prime.
It is not a weakly prime, because it can be changed into another prime (111112130126323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556065060661 + 55556065060662.
It is an arithmetic number, because the mean of its divisors is an integer number (55556065060662).
Almost surely, 2111112130121323 is an apocalyptic number.
111112130121323 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112130121323 is an equidigital number, since it uses as much as digits as its factorization.
111112130121323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 111112130121323 its reverse (323121031211111), we get a palindrome (434233161332434).
The spelling of 111112130121323 in words is "one hundred eleven trillion, one hundred twelve billion, one hundred thirty million, one hundred twenty-one thousand, three hundred twenty-three".
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