Base | Representation |
---|---|
bin | 1010000110110000100001… |
… | …1001011001111010100011 |
3 | 1110100020000010002201020012 |
4 | 2201230020121121322203 |
5 | 2424021240121202402 |
6 | 35344231413235135 |
7 | 2224521264330236 |
oct | 241541031317243 |
9 | 43306003081205 |
10 | 11111221272227 |
11 | 35a4273814a0a |
12 | 12b5519632aab |
13 | 627a2595293b |
14 | 2a5b00a2541d |
15 | 144065ae0452 |
hex | a1b08659ea3 |
11111221272227 has 2 divisors, whose sum is σ = 11111221272228. Its totient is φ = 11111221272226.
The previous prime is 11111221272211. The next prime is 11111221272241. The reversal of 11111221272227 is 72227212211111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11111221272227 - 24 = 11111221272211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11111221272193 and 11111221272202.
It is not a weakly prime, because it can be changed into another prime (11111221202227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555610636113 + 5555610636114.
It is an arithmetic number, because the mean of its divisors is an integer number (5555610636114).
Almost surely, 211111221272227 is an apocalyptic number.
11111221272227 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111221272227 is an equidigital number, since it uses as much as digits as its factorization.
11111221272227 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3136, while the sum is 32.
Adding to 11111221272227 its reverse (72227212211111), we get a palindrome (83338433483338).
The spelling of 11111221272227 in words is "eleven trillion, one hundred eleven billion, two hundred twenty-one million, two hundred seventy-two thousand, two hundred twenty-seven".
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