Base | Representation |
---|---|
bin | 11001010000111001011001… |
… | …001011011111010000000010 |
3 | 112120102020021020110221222110 |
4 | 121100321121023133100002 |
5 | 104030430442313200310 |
6 | 1032152141435520150 |
7 | 32255412243605361 |
oct | 3120713113372002 |
9 | 476366236427873 |
10 | 111112300131330 |
11 | 32449509806983 |
12 | 105663845b9056 |
13 | 49ccaca456a44 |
14 | 1d61c14c317d8 |
15 | cca444e6bd20 |
hex | 650e592df402 |
111112300131330 has 128 divisors (see below), whose sum is σ = 270030042455040. Its totient is φ = 29259097620480.
The previous prime is 111112300131323. The next prime is 111112300131377. The reversal of 111112300131330 is 33131003211111.
It is a junction number, because it is equal to n+sod(n) for n = 111112300131297 and 111112300131306.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 920345370 + ... + 920466090.
It is an arithmetic number, because the mean of its divisors is an integer number (2109609706680).
Almost surely, 2111112300131330 is an apocalyptic number.
111112300131330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
111112300131330 is an abundant number, since it is smaller than the sum of its proper divisors (158917742323710).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111112300131330 is a wasteful number, since it uses less digits than its factorization.
111112300131330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 122044.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 111112300131330 its reverse (33131003211111), we get a palindrome (144243303342441).
The spelling of 111112300131330 in words is "one hundred eleven trillion, one hundred twelve billion, three hundred million, one hundred thirty-one thousand, three hundred thirty".
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