Base | Representation |
---|---|
bin | 1010000110110000100111… |
… | …0000100100010101001111 |
3 | 1110100020001201002120102201 |
4 | 2201230021300210111033 |
5 | 2424021311443341143 |
6 | 35344233551102331 |
7 | 2224521662464045 |
oct | 241541160442517 |
9 | 43306051076381 |
10 | 11111244121423 |
11 | 35a4285700946 |
12 | 12b55252119a7 |
13 | 627a2a5c2b84 |
14 | 2a5b03a92395 |
15 | 144067b0564d |
hex | a1b09c2454f |
11111244121423 has 2 divisors, whose sum is σ = 11111244121424. Its totient is φ = 11111244121422.
The previous prime is 11111244121399. The next prime is 11111244121427. The reversal of 11111244121423 is 32412144211111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11111244121423 - 233 = 11102654186831 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11111244121391 and 11111244121400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11111244121427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555622060711 + 5555622060712.
It is an arithmetic number, because the mean of its divisors is an integer number (5555622060712).
Almost surely, 211111244121423 is an apocalyptic number.
11111244121423 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111244121423 is an equidigital number, since it uses as much as digits as its factorization.
11111244121423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1536, while the sum is 28.
Adding to 11111244121423 its reverse (32412144211111), we get a palindrome (43523388332534).
The spelling of 11111244121423 in words is "eleven trillion, one hundred eleven billion, two hundred forty-four million, one hundred twenty-one thousand, four hundred twenty-three".
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