111113000041 has 2 divisors, whose sum is σ = 111113000042. Its totient is φ = 111113000040.

The previous prime is 111113000021. The next prime is 111113000081. The reversal of 111113000041 is 140000311111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78579302400 + 32533697641 = 280320^2 + 180371^2 .

It is a cyclic number.

It is not a de Polignac number, because 111113000041 - 2¹³ = 111112991849 is a prime.

It is a super-2 number, since 2×111113000041² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111112999985 and 111113000030.

It is not a weakly prime, because it can be changed into another prime (111113000021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556500020 + 55556500021.

It is an arithmetic number, because the mean of its divisors is an integer number (55556500021).

Almost surely, 2^111113000041 is an apocalyptic number.

It is an amenable number.

111113000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

111113000041 is an equidigital number, since it uses as much as digits as its factorization.

111113000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 111113000041 its reverse (140000311111), we get a palindrome (251113311152).

The spelling of 111113000041 in words is "one hundred eleven billion, one hundred thirteen million, forty-one", and thus it is an aban number.