11111304401 has 2 divisors, whose sum is σ = 11111304402. Its totient is φ = 11111304400.

The previous prime is 11111304317. The next prime is 11111304403. The reversal of 11111304401 is 10440311111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8859327376 + 2251977025 = 94124^2 + 47455^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111304401 - 2²² = 11107110097 is a prime.

It is a super-2 number, since 2×11111304401² (a number of 21 digits) contains 22 as substring.

Together with 11111304403, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11111304401.

It is not a weakly prime, because it can be changed into another prime (11111304403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555652200 + 5555652201.

It is an arithmetic number, because the mean of its divisors is an integer number (5555652201).

Almost surely, 2^11111304401 is an apocalyptic number.

It is an amenable number.

11111304401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111304401 is an equidigital number, since it uses as much as digits as its factorization.

11111304401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11111304401 its reverse (10440311111), we get a palindrome (21551615512).

The spelling of 11111304401 in words is "eleven billion, one hundred eleven million, three hundred four thousand, four hundred one".