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1111131000022 = 2555565500011
BaseRepresentation
bin10000001010110100100…
…100011000110011010110
310221020000122000011012211
4100022310210120303112
5121201044014000042
62210240241304034
7143163601444441
oct20126444306326
93836018004184
101111131000022
1139925653406a
1215b41763501a
1380a18bab614
143bac9918658
151dd82cba017
hex102b4918cd6

1111131000022 has 4 divisors (see below), whose sum is σ = 1666696500036. Its totient is φ = 555565500010.

The previous prime is 1111131000013. The next prime is 1111131000041. The reversal of 1111131000022 is 2200001311111.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11111310000222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1111130999966 and 1111131000011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277782750004 + ... + 277782750007.

It is an arithmetic number, because the mean of its divisors is an integer number (416674125009).

Almost surely, 21111131000022 is an apocalyptic number.

1111131000022 is a deficient number, since it is larger than the sum of its proper divisors (555565500014).

1111131000022 is an equidigital number, since it uses as much as digits as its factorization.

1111131000022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 555565500013.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1111131000022 its reverse (2200001311111), we get a palindrome (3311132311133).

The spelling of 1111131000022 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, twenty-two", and thus it is an aban number.

Divisors: 1 2 555565500011 1111131000022