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111113210003 is a prime number
BaseRepresentation
bin110011101111011011…
…1010000100010010011
3101121210200002220102012
41213132313100202103
53310024440210003
6123013353413135
711012326462445
oct1473667204223
9347720086365
10111113210003
1143139568284
121964b70a1ab
13a62a024553
145540da0495
152d54bdc8d8
hex19dedd0893

111113210003 has 2 divisors, whose sum is σ = 111113210004. Its totient is φ = 111113210002.

The previous prime is 111113209981. The next prime is 111113210011. The reversal of 111113210003 is 300012311111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111113210003 - 28 = 111113209747 is a prime.

It is a super-2 number, since 2×1111132100032 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111113210003.

It is not a weakly prime, because it can be changed into another prime (111113219003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556605001 + 55556605002.

It is an arithmetic number, because the mean of its divisors is an integer number (55556605002).

Almost surely, 2111113210003 is an apocalyptic number.

111113210003 is a deficient number, since it is larger than the sum of its proper divisors (1).

111113210003 is an equidigital number, since it uses as much as digits as its factorization.

111113210003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 111113210003 its reverse (300012311111), we get a palindrome (411125521114).

The spelling of 111113210003 in words is "one hundred eleven billion, one hundred thirteen million, two hundred ten thousand, three".