Base | Representation |
---|---|
bin | 110011101111011011… |
… | …1010000100010010011 |
3 | 101121210200002220102012 |
4 | 1213132313100202103 |
5 | 3310024440210003 |
6 | 123013353413135 |
7 | 11012326462445 |
oct | 1473667204223 |
9 | 347720086365 |
10 | 111113210003 |
11 | 43139568284 |
12 | 1964b70a1ab |
13 | a62a024553 |
14 | 5540da0495 |
15 | 2d54bdc8d8 |
hex | 19dedd0893 |
111113210003 has 2 divisors, whose sum is σ = 111113210004. Its totient is φ = 111113210002.
The previous prime is 111113209981. The next prime is 111113210011. The reversal of 111113210003 is 300012311111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111113210003 - 28 = 111113209747 is a prime.
It is a super-2 number, since 2×1111132100032 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111113210003.
It is not a weakly prime, because it can be changed into another prime (111113219003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556605001 + 55556605002.
It is an arithmetic number, because the mean of its divisors is an integer number (55556605002).
Almost surely, 2111113210003 is an apocalyptic number.
111113210003 is a deficient number, since it is larger than the sum of its proper divisors (1).
111113210003 is an equidigital number, since it uses as much as digits as its factorization.
111113210003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 111113210003 its reverse (300012311111), we get a palindrome (411125521114).
The spelling of 111113210003 in words is "one hundred eleven billion, one hundred thirteen million, two hundred ten thousand, three".
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