Base | Representation |
---|---|
bin | 10100101100100100… |
… | …11001110011110101 |
3 | 1001200100221121210022 |
4 | 22112102121303311 |
5 | 140224000410201 |
6 | 5034322334525 |
7 | 542230562024 |
oct | 122622316365 |
9 | 31610847708 |
10 | 11111341301 |
11 | 47920761a5 |
12 | 21a11ba445 |
13 | 108100c388 |
14 | 7759b48bb |
15 | 45073441b |
hex | 296499cf5 |
11111341301 has 2 divisors, whose sum is σ = 11111341302. Its totient is φ = 11111341300.
The previous prime is 11111341291. The next prime is 11111341313. The reversal of 11111341301 is 10314311111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11014712401 + 96628900 = 104951^2 + 9830^2 .
It is a cyclic number.
It is not a de Polignac number, because 11111341301 - 26 = 11111341237 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11111341301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11111041301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555670650 + 5555670651.
It is an arithmetic number, because the mean of its divisors is an integer number (5555670651).
Almost surely, 211111341301 is an apocalyptic number.
It is an amenable number.
11111341301 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111341301 is an equidigital number, since it uses as much as digits as its factorization.
11111341301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 11111341301 its reverse (10314311111), we get a palindrome (21425652412).
The spelling of 11111341301 in words is "eleven billion, one hundred eleven million, three hundred forty-one thousand, three hundred one".
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