Base | Representation |
---|---|
bin | 1010000110110011011101… |
… | …1010111011010010111011 |
3 | 1110100022001002121102000122 |
4 | 2201230313122323102323 |
5 | 2424024344102402001 |
6 | 35344441554523455 |
7 | 2224546654161032 |
oct | 241546732732273 |
9 | 43308032542018 |
10 | 11112010200251 |
11 | 35a4639083244 |
12 | 12b56b989658b |
13 | 627b2022a05c |
14 | 2a5b7770b719 |
15 | 1440aeecbb1b |
hex | a1b376bb4bb |
11112010200251 has 2 divisors, whose sum is σ = 11112010200252. Its totient is φ = 11112010200250.
The previous prime is 11112010200191. The next prime is 11112010200253. The reversal of 11112010200251 is 15200201021111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11112010200251 is a prime.
Together with 11112010200253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11112010200253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556005100125 + 5556005100126.
It is an arithmetic number, because the mean of its divisors is an integer number (5556005100126).
Almost surely, 211112010200251 is an apocalyptic number.
11112010200251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112010200251 is an equidigital number, since it uses as much as digits as its factorization.
11112010200251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 11112010200251 its reverse (15200201021111), we get a palindrome (26312211221362).
The spelling of 11112010200251 in words is "eleven trillion, one hundred twelve billion, ten million, two hundred thousand, two hundred fifty-one".
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