Base | Representation |
---|---|
bin | 10100101100101001… |
… | …11111011001001011 |
3 | 1001200102020002010221 |
4 | 22112110333121023 |
5 | 140224134111111 |
6 | 5034345050511 |
7 | 542236415254 |
oct | 122624773113 |
9 | 31612202127 |
10 | 11112019531 |
11 | 4792499818 |
12 | 21a1486a37 |
13 | 10811b8cb2 |
14 | 775b0db2b |
15 | 45081a371 |
hex | 29653f64b |
11112019531 has 2 divisors, whose sum is σ = 11112019532. Its totient is φ = 11112019530.
The previous prime is 11112019511. The next prime is 11112019549. The reversal of 11112019531 is 13591021111.
It is a strong prime.
It is an emirp because it is prime and its reverse (13591021111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11112019531 - 27 = 11112019403 is a prime.
It is a super-2 number, since 2×111120195312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11112019496 and 11112019505.
It is not a weakly prime, because it can be changed into another prime (11112019511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556009765 + 5556009766.
It is an arithmetic number, because the mean of its divisors is an integer number (5556009766).
Almost surely, 211112019531 is an apocalyptic number.
11112019531 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112019531 is an equidigital number, since it uses as much as digits as its factorization.
11112019531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270, while the sum is 25.
The spelling of 11112019531 in words is "eleven billion, one hundred twelve million, nineteen thousand, five hundred thirty-one".
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