1111209977453 has 2 divisors, whose sum is σ = 1111209977454. Its totient is φ = 1111209977452.

The previous prime is 1111209977443. The next prime is 1111209977461. The reversal of 1111209977453 is 3547799021111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 780743658409 + 330466319044 = 883597^2 + 574862^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111209977453 - 2⁶ = 1111209977389 is a prime.

It is a super-2 number, since 2×1111209977453² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111209977443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555604988726 + 555604988727.

It is an arithmetic number, because the mean of its divisors is an integer number (555604988727).

Almost surely, 2^{1111209977453} is an apocalyptic number.

It is an amenable number.

1111209977453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111209977453 is an equidigital number, since it uses as much as digits as its factorization.

1111209977453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 476280, while the sum is 50.

The spelling of 1111209977453 in words is "one trillion, one hundred eleven billion, two hundred nine million, nine hundred seventy-seven thousand, four hundred fifty-three".