Base | Representation |
---|---|
bin | 1010000110110011110011… |
… | …1001111000011010101111 |
3 | 1110100022021111201112100001 |
4 | 2201230330321320122233 |
5 | 2424030041130413012 |
6 | 35344455042445131 |
7 | 2224552152155563 |
oct | 241547471703257 |
9 | 43308244645301 |
10 | 11112102201007 |
11 | 35a4686000825 |
12 | 12b57246637a7 |
13 | 627b362cc882 |
14 | 2a5b85a196a3 |
15 | 1440b8101357 |
hex | a1b3ce786af |
11112102201007 has 2 divisors, whose sum is σ = 11112102201008. Its totient is φ = 11112102201006.
The previous prime is 11112102200993. The next prime is 11112102201059. The reversal of 11112102201007 is 70010220121111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11112102201007 - 215 = 11112102168239 is a prime.
It is a super-3 number, since 3×111121022010073 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11112102301007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556051100503 + 5556051100504.
It is an arithmetic number, because the mean of its divisors is an integer number (5556051100504).
Almost surely, 211112102201007 is an apocalyptic number.
11112102201007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112102201007 is an equidigital number, since it uses as much as digits as its factorization.
11112102201007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 11112102201007 its reverse (70010220121111), we get a palindrome (81122322322118).
The spelling of 11112102201007 in words is "eleven trillion, one hundred twelve billion, one hundred two million, two hundred one thousand, seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •