Base | Representation |
---|---|
bin | 1010000110110011110111… |
… | …1101110100010100010011 |
3 | 1110100022022202020022200111 |
4 | 2201230331331310110103 |
5 | 2424030110210310003 |
6 | 35344500520302151 |
7 | 2224552456431055 |
oct | 241547575642423 |
9 | 43308282208614 |
10 | 11112120010003 |
11 | 35a4695064a01 |
12 | 12b572a611957 |
13 | 627b39bc693c |
14 | 2a5b881338d5 |
15 | 1440b996ce6d |
hex | a1b3df74513 |
11112120010003 has 2 divisors, whose sum is σ = 11112120010004. Its totient is φ = 11112120010002.
The previous prime is 11112120009929. The next prime is 11112120010009. The reversal of 11112120010003 is 30001002121111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11112120010003 is a prime.
It is a super-2 number, since 2×111121200100032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11112120010009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556060005001 + 5556060005002.
It is an arithmetic number, because the mean of its divisors is an integer number (5556060005002).
Almost surely, 211112120010003 is an apocalyptic number.
11112120010003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112120010003 is an equidigital number, since it uses as much as digits as its factorization.
11112120010003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 11112120010003 its reverse (30001002121111), we get a palindrome (41113122131114).
The spelling of 11112120010003 in words is "eleven trillion, one hundred twelve billion, one hundred twenty million, ten thousand, three".
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