111121403340037 has 2 divisors, whose sum is σ = 111121403340038. Its totient is φ = 111121403340036.

The previous prime is 111121403339911. The next prime is 111121403340109. The reversal of 111121403340037 is 730043304121111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82220898245476 + 28900505094561 = 9067574^2 + 5375919^2 .

It is a cyclic number.

It is not a de Polignac number, because 111121403340037 - 2¹⁵ = 111121403307269 is a prime.

It is a super-2 number, since 2×111121403340037² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111121403339990 and 111121403340008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111121403341037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55560701670018 + 55560701670019.

It is an arithmetic number, because the mean of its divisors is an integer number (55560701670019).

Almost surely, 2^{111121403340037} is an apocalyptic number.

It is an amenable number.

111121403340037 is a deficient number, since it is larger than the sum of its proper divisors (1).

111121403340037 is an equidigital number, since it uses as much as digits as its factorization.

111121403340037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 111121403340037 its reverse (730043304121111), we get a palindrome (841164707461148).

The spelling of 111121403340037 in words is "one hundred eleven trillion, one hundred twenty-one billion, four hundred three million, three hundred forty thousand, thirty-seven".