1111214051 has 2 divisors, whose sum is σ = 1111214052. Its totient is φ = 1111214050.

The previous prime is 1111214033. The next prime is 1111214053. The reversal of 1111214051 is 1504121111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1111214051 - 2²² = 1107019747 is a prime.

Together with 1111214053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1111214053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555607025 + 555607026.

It is an arithmetic number, because the mean of its divisors is an integer number (555607026).

Almost surely, 2^1111214051 is an apocalyptic number.

1111214051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111214051 is an equidigital number, since it uses as much as digits as its factorization.

1111214051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40, while the sum is 17.

The square root of 1111214051 is about 33334.8773959047. The cubic root of 1111214051 is about 1035.7761534804.

Adding to 1111214051 its reverse (1504121111), we get a palindrome (2615335162).

The spelling of 1111214051 in words is "one billion, one hundred eleven million, two hundred fourteen thousand, fifty-one".