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1111221001997 is a prime number
BaseRepresentation
bin10000001010111001111…
…011101101111100001101
310221020020220100201201022
4100022321323231330031
5121201240034030442
62210253214323525
7143166043446041
oct20127173557415
93836226321638
101111221001997
113992a2316967
1215b4417b95a5
1380a31731422
143bad7866021
151dd8ab473d2
hex102b9eedf0d

1111221001997 has 2 divisors, whose sum is σ = 1111221001998. Its totient is φ = 1111221001996.

The previous prime is 1111221001909. The next prime is 1111221002051. The reversal of 1111221001997 is 7991001221111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 940161005161 + 171059996836 = 969619^2 + 413594^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111221001997 - 28 = 1111221001741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111221006997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555610500998 + 555610500999.

It is an arithmetic number, because the mean of its divisors is an integer number (555610500999).

Almost surely, 21111221001997 is an apocalyptic number.

It is an amenable number.

1111221001997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111221001997 is an equidigital number, since it uses as much as digits as its factorization.

1111221001997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 35.

The spelling of 1111221001997 in words is "one trillion, one hundred eleven billion, two hundred twenty-one million, one thousand, nine hundred ninety-seven".