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1111221112019 is a prime number
BaseRepresentation
bin10000001010111001111…
…100001000110011010011
310221020020220120022122012
4100022321330020303103
5121201240101041034
62210253220533135
7143166044414564
oct20127174106323
93836226508565
101111221112019
113992a2391597
1215b4418511ab
1380a3176c525
143bad789416b
151dd8ab69cce
hex102b9f08cd3

1111221112019 has 2 divisors, whose sum is σ = 1111221112020. Its totient is φ = 1111221112018.

The previous prime is 1111221111989. The next prime is 1111221112021. The reversal of 1111221112019 is 9102111221111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1111221112019 - 212 = 1111221107923 is a prime.

It is a super-2 number, since 2×11112211120192 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1111221112021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111221111985 and 1111221112003.

It is not a weakly prime, because it can be changed into another prime (1111221112069) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555610556009 + 555610556010.

It is an arithmetic number, because the mean of its divisors is an integer number (555610556010).

Almost surely, 21111221112019 is an apocalyptic number.

1111221112019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111221112019 is an equidigital number, since it uses as much as digits as its factorization.

1111221112019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 23.

The spelling of 1111221112019 in words is "one trillion, one hundred eleven billion, two hundred twenty-one million, one hundred twelve thousand, nineteen".