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11112212202041 is a prime number
BaseRepresentation
bin1010000110110100001101…
…1101100000001000111001
31110100022120011201011101102
42201231003131200020321
52424030302310431131
635344514012301145
72224554656153366
oct241550335401071
943308504634342
1011112212202041
1135a4732103175
1212b57554717b5
13627b53035542
142a5b9649146d
151440c2ace1cb
hexa1b43760239

11112212202041 has 2 divisors, whose sum is σ = 11112212202042. Its totient is φ = 11112212202040.

The previous prime is 11112212202037. The next prime is 11112212202043. The reversal of 11112212202041 is 14020221221111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6521460301225 + 4590751900816 = 2553715^2 + 2142604^2 .

It is a cyclic number.

It is not a de Polignac number, because 11112212202041 - 22 = 11112212202037 is a prime.

Together with 11112212202043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11112212202043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556106101020 + 5556106101021.

It is an arithmetic number, because the mean of its divisors is an integer number (5556106101021).

Almost surely, 211112212202041 is an apocalyptic number.

It is an amenable number.

11112212202041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11112212202041 is an equidigital number, since it uses as much as digits as its factorization.

11112212202041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 11112212202041 its reverse (14020221221111), we get a palindrome (25132433423152).

The spelling of 11112212202041 in words is "eleven trillion, one hundred twelve billion, two hundred twelve million, two hundred two thousand, forty-one".