Base | Representation |
---|---|
bin | 10000001010111010000… |
… | …011011101010101011101 |
3 | 10221020021001011211011111 |
4 | 100022322003131111131 |
5 | 121201241043444013 |
6 | 2210253330022021 |
7 | 143166066626635 |
oct | 20127203352535 |
9 | 3836231154144 |
10 | 1111223031133 |
11 | 3992a3482436 |
12 | 15b442417911 |
13 | 80a31c91bb7 |
14 | 3bad7c336c5 |
15 | 1dd8ade873d |
hex | 102ba0dd55d |
1111223031133 has 2 divisors, whose sum is σ = 1111223031134. Its totient is φ = 1111223031132.
The previous prime is 1111223031109. The next prime is 1111223031151. The reversal of 1111223031133 is 3311303221111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1107299512089 + 3923519044 = 1052283^2 + 62638^2 .
It is an emirp because it is prime and its reverse (3311303221111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111223031133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111223031173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555611515566 + 555611515567.
It is an arithmetic number, because the mean of its divisors is an integer number (555611515567).
Almost surely, 21111223031133 is an apocalyptic number.
It is an amenable number.
1111223031133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111223031133 is an equidigital number, since it uses as much as digits as its factorization.
1111223031133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1111223031133 its reverse (3311303221111), we get a palindrome (4422526252244).
The spelling of 1111223031133 in words is "one trillion, one hundred eleven billion, two hundred twenty-three million, thirty-one thousand, one hundred thirty-three".
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