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11112240213331 is a prime number
BaseRepresentation
bin1010000110110100010100…
…1000010110110101010011
31110100022122010102021122121
42201231011020112311103
52424030331443311311
635344520452515111
72224555446230065
oct241550510266523
943308563367577
1011112240213331
1135a47469a54a4
1212b576291ba97
13627b58a9227a
142a5b9a0a3735
151440c52b3b71
hexa1b45216d53

11112240213331 has 2 divisors, whose sum is σ = 11112240213332. Its totient is φ = 11112240213330.

The previous prime is 11112240213313. The next prime is 11112240213397. The reversal of 11112240213331 is 13331204221111.

Together with previous prime (11112240213313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11112240213331 - 217 = 11112240082259 is a prime.

It is a super-2 number, since 2×111122402133312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11112240213296 and 11112240213305.

It is not a weakly prime, because it can be changed into another prime (11112240213631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556120106665 + 5556120106666.

It is an arithmetic number, because the mean of its divisors is an integer number (5556120106666).

Almost surely, 211112240213331 is an apocalyptic number.

11112240213331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11112240213331 is an equidigital number, since it uses as much as digits as its factorization.

11112240213331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 11112240213331 its reverse (13331204221111), we get a palindrome (24443444434442).

The spelling of 11112240213331 in words is "eleven trillion, one hundred twelve billion, two hundred forty million, two hundred thirteen thousand, three hundred thirty-one".