Base | Representation |
---|---|
bin | 10000001010111010001… |
… | …011000110010110111101 |
3 | 10221020021011221120211011 |
4 | 100022322023012112331 |
5 | 121201242102043143 |
6 | 2210253440555221 |
7 | 143166122641462 |
oct | 20127213062675 |
9 | 3836234846734 |
10 | 1111225034173 |
11 | 3992a4620341 |
12 | 15b443022b11 |
13 | 80a32513827 |
14 | 3bad81d5669 |
15 | 1dd8b191e9d |
hex | 102ba2c65bd |
1111225034173 has 2 divisors, whose sum is σ = 1111225034174. Its totient is φ = 1111225034172.
The previous prime is 1111225034131. The next prime is 1111225034191. The reversal of 1111225034173 is 3714305221111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 698992979364 + 412232054809 = 836058^2 + 642053^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111225034173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111225034123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555612517086 + 555612517087.
It is an arithmetic number, because the mean of its divisors is an integer number (555612517087).
Almost surely, 21111225034173 is an apocalyptic number.
It is an amenable number.
1111225034173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111225034173 is an equidigital number, since it uses as much as digits as its factorization.
1111225034173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 31.
The spelling of 1111225034173 in words is "one trillion, one hundred eleven billion, two hundred twenty-five million, thirty-four thousand, one hundred seventy-three".
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