Base | Representation |
---|---|
bin | 110011101111101111… |
… | …0010010001001100111 |
3 | 101121211101100122122112 |
4 | 1213133132102021213 |
5 | 3310040100041411 |
6 | 123014400551235 |
7 | 11012512441256 |
oct | 1473736221147 |
9 | 347741318575 |
10 | 111123440231 |
11 | 43144315411 |
12 | 1965302251b |
13 | a62c196b3b |
14 | 55424a479d |
15 | 2d55a5db8b |
hex | 19df792267 |
111123440231 has 2 divisors, whose sum is σ = 111123440232. Its totient is φ = 111123440230.
The previous prime is 111123440179. The next prime is 111123440237. The reversal of 111123440231 is 132044321111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111123440231 - 218 = 111123178087 is a prime.
It is a super-2 number, since 2×1111234402312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111123440197 and 111123440206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111123440237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55561720115 + 55561720116.
It is an arithmetic number, because the mean of its divisors is an integer number (55561720116).
Almost surely, 2111123440231 is an apocalyptic number.
111123440231 is a deficient number, since it is larger than the sum of its proper divisors (1).
111123440231 is an equidigital number, since it uses as much as digits as its factorization.
111123440231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 111123440231 its reverse (132044321111), we get a palindrome (243167761342).
The spelling of 111123440231 in words is "one hundred eleven billion, one hundred twenty-three million, four hundred forty thousand, two hundred thirty-one".
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