Base | Representation |
---|---|
bin | 1010000110110111001100… |
… | …0101110101011110000111 |
3 | 1110100101121212100202122101 |
4 | 2201231303011311132013 |
5 | 2424033421343214302 |
6 | 35345125200012531 |
7 | 2224613531340562 |
oct | 241556305653607 |
9 | 43311555322571 |
10 | 11113011304327 |
11 | 35a5002190589 |
12 | 12b5939001147 |
13 | 627c4c76292a |
14 | 2a5c306654d9 |
15 | 14411cd2a287 |
hex | a1b73175787 |
11113011304327 has 2 divisors, whose sum is σ = 11113011304328. Its totient is φ = 11113011304326.
The previous prime is 11113011304309. The next prime is 11113011304361. The reversal of 11113011304327 is 72340311031111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11113011304327 - 215 = 11113011271559 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11113011304295 and 11113011304304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11113011308327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556505652163 + 5556505652164.
It is an arithmetic number, because the mean of its divisors is an integer number (5556505652164).
Almost surely, 211113011304327 is an apocalyptic number.
11113011304327 is a deficient number, since it is larger than the sum of its proper divisors (1).
11113011304327 is an equidigital number, since it uses as much as digits as its factorization.
11113011304327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 11113011304327 its reverse (72340311031111), we get a palindrome (83453322335438).
The spelling of 11113011304327 in words is "eleven trillion, one hundred thirteen billion, eleven million, three hundred four thousand, three hundred twenty-seven".
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