11113021993 has 2 divisors, whose sum is σ = 11113021994. Its totient is φ = 11113021992.

The previous prime is 11113021991. The next prime is 11113022003. The reversal of 11113021993 is 39912031111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5992617744 + 5120404249 = 77412^2 + 71557^2 .

It is a cyclic number.

It is not a de Polignac number, because 11113021993 - 2¹ = 11113021991 is a prime.

Together with 11113021991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11113021991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556510996 + 5556510997.

It is an arithmetic number, because the mean of its divisors is an integer number (5556510997).

Almost surely, 2^11113021993 is an apocalyptic number.

It is an amenable number.

11113021993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113021993 is an equidigital number, since it uses as much as digits as its factorization.

11113021993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 31.

The spelling of 11113021993 in words is "eleven billion, one hundred thirteen million, twenty-one thousand, nine hundred ninety-three".