11113132320133 has 4 divisors (see below), whose sum is σ = 11140845867468. Its totient is φ = 11085418772800.

The previous prime is 11113132320091. The next prime is 11113132320149. The reversal of 11113132320133 is 33102323131111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7109779617889 + 4003352702244 = 2666417^2 + 2000838^2 .

It is a cyclic number.

It is not a de Polignac number, because 11113132320133 - 2²⁵ = 11113098765701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11113132320098 and 11113132320107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11113132320163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13856773066 + ... + 13856773867.

It is an arithmetic number, because the mean of its divisors is an integer number (2785211466867).

Almost surely, 2^{11113132320133} is an apocalyptic number.

It is an amenable number.

11113132320133 is a deficient number, since it is larger than the sum of its proper divisors (27713547335).

11113132320133 is an equidigital number, since it uses as much as digits as its factorization.

11113132320133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27713547334.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11113132320133 its reverse (33102323131111), we get a palindrome (44215455451244).

The spelling of 11113132320133 in words is "eleven trillion, one hundred thirteen billion, one hundred thirty-two million, three hundred twenty thousand, one hundred thirty-three".