11113140000000 has 576 divisors, whose sum is σ = 38583594975744. Its totient is φ = 2834304000000.

The previous prime is 11113139999981. The next prime is 11113140000037. The reversal of 11113140000000 is 4131111.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1379995974 + ... + 1380004026.

It is an arithmetic number, because the mean of its divisors is an integer number (66985407944).

Almost surely, 2^{11113140000000} is an apocalyptic number.

11113140000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11113140000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19291797487872).

11113140000000 is an abundant number, since it is smaller than the sum of its proper divisors (27470454975744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11113140000000 is an frugal number, since it uses more digits than its factorization.

11113140000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8130 (or 8086 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 11113140000000 its reverse (4131111), we get a palindrome (11113144131111).

The spelling of 11113140000000 in words is "eleven trillion, one hundred thirteen billion, one hundred forty million", and thus it is an aban number.