Base | Representation |
---|---|

bin | 100001000111101… |

… | …0110010111000000 |

3 | 2212110010220110000 |

4 | 1002033112113000 |

5 | 4233444220000 |

6 | 302135240000 |

7 | 36353031000 |

oct | 10217262700 |

9 | 2773126400 |

10 | 1111320000 |

11 | 52034718a |

12 | 270219000 |

13 | 1493152cb |

14 | a7848000 |

15 | 67870000 |

hex | 423d65c0 |

1111320000 has 700 divisors, whose sum is σ = 4800650800. Its totient is φ = 254016000.

The previous prime is 1111319999. The next prime is 1111320011. The reversal of 1111320000 is 231111.

It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.

It is a tau number, because it is divible by the number of its divisors (700).

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 99 ways as a sum of consecutive naturals, for example, 158759997 + ... + 158760003.

Almost surely, 2^{1111320000} is an apocalyptic number.

1111320000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1111320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2400325400).

1111320000 is an abundant number, since it is smaller than the sum of its proper divisors (3689330800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1111320000 is an frugal number, since it uses more digits than its factorization.

1111320000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65 (or 17 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

The square root of 1111320000 is about 33336.4665194138. The cubic root of 1111320000 is about 1035.8090712188.

Adding to 1111320000 its reverse (231111), we get a palindrome (1111551111).

Subtracting from 1111320000 its reverse (231111), we obtain a square (1111088889 = 33333^{2}).

It can be divided in two parts, 11113 and 20000, that added together give a palindrome (31113).

The spelling of 1111320000 in words is "one billion, one hundred eleven million, three hundred twenty thousand".

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