Base | Representation |
---|---|
bin | 1010000110110111111011… |
… | …1100101110010010010001 |
3 | 1110100102010201200212002111 |
4 | 2201231332330232102101 |
5 | 2424034323310222233 |
6 | 35345201023545321 |
7 | 2224621465312423 |
oct | 241557674562221 |
9 | 43312121625074 |
10 | 11113210242193 |
11 | 35a50a4508544 |
12 | 12b599375b241 |
13 | 627c81a37647 |
14 | 2a5c4cc4c813 |
15 | 144130524acd |
hex | a1b7ef2e491 |
11113210242193 has 2 divisors, whose sum is σ = 11113210242194. Its totient is φ = 11113210242192.
The previous prime is 11113210242181. The next prime is 11113210242221. The reversal of 11113210242193 is 39124201231111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9806962402449 + 1306247839744 = 3131607^2 + 1142912^2 .
It is a cyclic number.
It is not a de Polignac number, because 11113210242193 - 213 = 11113210234001 is a prime.
It is not a weakly prime, because it can be changed into another prime (11113210242133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556605121096 + 5556605121097.
It is an arithmetic number, because the mean of its divisors is an integer number (5556605121097).
Almost surely, 211113210242193 is an apocalyptic number.
It is an amenable number.
11113210242193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11113210242193 is an equidigital number, since it uses as much as digits as its factorization.
11113210242193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 11113210242193 in words is "eleven trillion, one hundred thirteen billion, two hundred ten million, two hundred forty-two thousand, one hundred ninety-three".
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