Base | Representation |
---|---|
bin | 10000001010111111111… |
… | …001010010111000100101 |
3 | 10221020111212120200120212 |
4 | 100022333321102320211 |
5 | 121201441140431211 |
6 | 2210311150305205 |
7 | 143201366616305 |
oct | 20127771227045 |
9 | 3836455520525 |
10 | 1111321030181 |
11 | 39934382758a |
12 | 15b46b1b8205 |
13 | 80a493849bb |
14 | 3bb06c63605 |
15 | 1dd9480538b |
hex | 102bfe52e25 |
1111321030181 has 2 divisors, whose sum is σ = 1111321030182. Its totient is φ = 1111321030180.
The previous prime is 1111321030153. The next prime is 1111321030213. The reversal of 1111321030181 is 1810301231111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1056288562081 + 55032468100 = 1027759^2 + 234590^2 .
It is a cyclic number.
It is not a de Polignac number, because 1111321030181 - 210 = 1111321029157 is a prime.
It is a super-2 number, since 2×11113210301812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111321030081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555660515090 + 555660515091.
It is an arithmetic number, because the mean of its divisors is an integer number (555660515091).
Almost surely, 21111321030181 is an apocalyptic number.
It is an amenable number.
1111321030181 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111321030181 is an equidigital number, since it uses as much as digits as its factorization.
1111321030181 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 23.
Adding to 1111321030181 its reverse (1810301231111), we get a palindrome (2921622261292).
The spelling of 1111321030181 in words is "one trillion, one hundred eleven billion, three hundred twenty-one million, thirty thousand, one hundred eighty-one".
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