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11113310213 is a prime number
BaseRepresentation
bin10100101100110011…
…11010100000000101
31001200111122122121222
422112121322200011
5140230001411323
65034432450125
7542253402215
oct122631724005
931614578558
1011113310213
1147931a04a5
1221a19a9945
13108154b605
14775d68245
154509c29c8
hex29667a805

11113310213 has 2 divisors, whose sum is σ = 11113310214. Its totient is φ = 11113310212.

The previous prime is 11113310209. The next prime is 11113310233. The reversal of 11113310213 is 31201331111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11101151044 + 12159169 = 105362^2 + 3487^2 .

It is an emirp because it is prime and its reverse (31201331111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11113310213 - 22 = 11113310209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11113310191 and 11113310200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11113310233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556655106 + 5556655107.

It is an arithmetic number, because the mean of its divisors is an integer number (5556655107).

Almost surely, 211113310213 is an apocalyptic number.

It is an amenable number.

11113310213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113310213 is an equidigital number, since it uses as much as digits as its factorization.

11113310213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11113310213 its reverse (31201331111), we get a palindrome (42314641324).

The spelling of 11113310213 in words is "eleven billion, one hundred thirteen million, three hundred ten thousand, two hundred thirteen".