Base | Representation |
---|---|
bin | 10100101100110100… |
… | …10110011000110001 |
3 | 1001200111212110022100 |
4 | 22112122112120301 |
5 | 140230014040213 |
6 | 5034435131013 |
7 | 542254356216 |
oct | 122632263061 |
9 | 31614773270 |
10 | 11113424433 |
11 | 47932692a1 |
12 | 21a1a43a69 |
13 | 108158b5b7 |
14 | 775d97b0d |
15 | 4509e6773 |
hex | 296696631 |
11113424433 has 96 divisors (see below), whose sum is σ = 17965449216. Its totient is φ = 6590191104.
The previous prime is 11113424423. The next prime is 11113424449. The reversal of 11113424433 is 33442431111.
It is not a de Polignac number, because 11113424433 - 25 = 11113424401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11113424397 and 11113424406.
It is not an unprimeable number, because it can be changed into a prime (11113424423) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 39269910 + ... + 39270192.
It is an arithmetic number, because the mean of its divisors is an integer number (187140096).
Almost surely, 211113424433 is an apocalyptic number.
It is an amenable number.
11113424433 is a deficient number, since it is larger than the sum of its proper divisors (6852024783).
11113424433 is a wasteful number, since it uses less digits than its factorization.
11113424433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 523 (or 520 counting only the distinct ones).
The product of its digits is 3456, while the sum is 27.
Adding to 11113424433 its reverse (33442431111), we get a palindrome (44555855544).
The spelling of 11113424433 in words is "eleven billion, one hundred thirteen million, four hundred twenty-four thousand, four hundred thirty-three".
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