11114014183 has 4 divisors (see below), whose sum is σ = 11166687448. Its totient is φ = 11061340920.

The previous prime is 11114014169. The next prime is 11114014187. The reversal of 11114014183 is 38141041111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 38141041111 = 47 ⋅811511513.

It is a cyclic number.

It is not a de Polignac number, because 11114014183 - 2⁹ = 11114013671 is a prime.

It is a super-2 number, since 2×11114014183² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11114014187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26336316 + ... + 26336737.

It is an arithmetic number, because the mean of its divisors is an integer number (2791671862).

Almost surely, 2^11114014183 is an apocalyptic number.

11114014183 is a deficient number, since it is larger than the sum of its proper divisors (52673265).

11114014183 is an equidigital number, since it uses as much as digits as its factorization.

11114014183 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52673264.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 11114014183 its reverse (38141041111), we get a palindrome (49255055294).

The spelling of 11114014183 in words is "eleven billion, one hundred fourteen million, fourteen thousand, one hundred eighty-three".