Base | Representation |
---|---|
bin | 1010000110111011101011… |
… | …0010100110110111100111 |
3 | 1110100111201200212101022020 |
4 | 2201232322302212313213 |
5 | 2424043402320121320 |
6 | 35345444410434223 |
7 | 2224655406104226 |
oct | 241567262466747 |
9 | 43314650771266 |
10 | 11114214223335 |
11 | 35a556a200423 |
12 | 12b6013a32973 |
13 | 6280b1a39922 |
14 | 2a5d06314cbd |
15 | 14418d740940 |
hex | a1bbaca6de7 |
11114214223335 has 32 divisors (see below), whose sum is σ = 18829468956672. Its totient is φ = 5578697464320.
The previous prime is 11114214223313. The next prime is 11114214223361. The reversal of 11114214223335 is 53332241241111.
It is not a de Polignac number, because 11114214223335 - 211 = 11114214221287 is a prime.
It is a super-3 number, since 3×111142142233353 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11114214223296 and 11114214223305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6386290 + ... + 7938080.
It is an arithmetic number, because the mean of its divisors is an integer number (588420904896).
Almost surely, 211114214223335 is an apocalyptic number.
11114214223335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11114214223335 is a deficient number, since it is larger than the sum of its proper divisors (7715254733337).
11114214223335 is a wasteful number, since it uses less digits than its factorization.
11114214223335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1579903.
The product of its digits is 17280, while the sum is 33.
Adding to 11114214223335 its reverse (53332241241111), we get a palindrome (64446455464446).
The spelling of 11114214223335 in words is "eleven trillion, one hundred fourteen billion, two hundred fourteen million, two hundred twenty-three thousand, three hundred thirty-five".
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