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11114404451 is a prime number
BaseRepresentation
bin10100101100111100…
…00101101001100011
31001200120201020122022
422112132011221203
5140230241420301
65034512132055
7542265610343
oct122636055143
931616636568
1011114404451
114793878627
1221a223702b
1310818426a7
14776170d23
15450b3bd1b
hex296785a63

11114404451 has 2 divisors, whose sum is σ = 11114404452. Its totient is φ = 11114404450.

The previous prime is 11114404387. The next prime is 11114404513. The reversal of 11114404451 is 15440441111.

It is a happy number.

11114404451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11114404451 - 26 = 11114404387 is a prime.

It is a super-2 number, since 2×111144044512 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11114404451.

It is not a weakly prime, because it can be changed into another prime (11114404051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557202225 + 5557202226.

It is an arithmetic number, because the mean of its divisors is an integer number (5557202226).

Almost surely, 211114404451 is an apocalyptic number.

11114404451 is a deficient number, since it is larger than the sum of its proper divisors (1).

11114404451 is an equidigital number, since it uses as much as digits as its factorization.

11114404451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1280, while the sum is 26.

Adding to 11114404451 its reverse (15440441111), we get a palindrome (26554845562).

The spelling of 11114404451 in words is "eleven billion, one hundred fourteen million, four hundred four thousand, four hundred fifty-one".