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11115100103 is a prime number
BaseRepresentation
bin10100101101000001…
…01111011111000111
31001200122000120220012
422112200233133013
5140230431200403
65034535100435
7542304535442
oct122640573707
931618016805
1011115100103
114794203248
1221a251171b
131081a27213
147762b2659
15450c27ed8
hex29682f7c7

11115100103 has 2 divisors, whose sum is σ = 11115100104. Its totient is φ = 11115100102.

The previous prime is 11115100097. The next prime is 11115100147. The reversal of 11115100103 is 30100151111.

It is a weak prime.

It is an emirp because it is prime and its reverse (30100151111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11115100103 - 26 = 11115100039 is a prime.

It is a super-2 number, since 2×111151001032 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11115160103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557550051 + 5557550052.

It is an arithmetic number, because the mean of its divisors is an integer number (5557550052).

Almost surely, 211115100103 is an apocalyptic number.

11115100103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11115100103 is an equidigital number, since it uses as much as digits as its factorization.

11115100103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 14.

Adding to 11115100103 its reverse (30100151111), we get a palindrome (41215251214).

The spelling of 11115100103 in words is "eleven billion, one hundred fifteen million, one hundred thousand, one hundred three".