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11115413124397 is a prime number
BaseRepresentation
bin1010000111000000001001…
…0000000011010100101101
31110100121211020210212101021
42201300002100003110231
52424103331224440042
635350203355214141
72225030204434501
oct241600220032455
943317736725337
1011115413124397
1135a6024a2654a
1212b62a9447351
13628243237b3a
142a5dbb63a301
1514420db10867
hexa1c0240352d

11115413124397 has 2 divisors, whose sum is σ = 11115413124398. Its totient is φ = 11115413124396.

The previous prime is 11115413124383. The next prime is 11115413124463. The reversal of 11115413124397 is 79342131451111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11108749014441 + 6664109956 = 3332979^2 + 81634^2 .

It is a cyclic number.

It is not a de Polignac number, because 11115413124397 - 27 = 11115413124269 is a prime.

It is a super-2 number, since 2×111154131243972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11115413124097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557706562198 + 5557706562199.

It is an arithmetic number, because the mean of its divisors is an integer number (5557706562199).

Almost surely, 211115413124397 is an apocalyptic number.

It is an amenable number.

11115413124397 is a deficient number, since it is larger than the sum of its proper divisors (1).

11115413124397 is an equidigital number, since it uses as much as digits as its factorization.

11115413124397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90720, while the sum is 43.

The spelling of 11115413124397 in words is "eleven trillion, one hundred fifteen billion, four hundred thirteen million, one hundred twenty-four thousand, three hundred ninety-seven".