Base | Representation |
---|---|
bin | 10000001011010110110… |
… | …011100110000111111101 |
3 | 10221021111122212022102222 |
4 | 100023112303212013331 |
5 | 121203233041141333 |
6 | 2210413241055125 |
7 | 143214045042263 |
oct | 20132663460775 |
9 | 3837448768388 |
10 | 1111705412093 |
11 | 3995207a5391 |
12 | 15b557a874a5 |
13 | 80aaabb8513 |
14 | 3bb41d20433 |
15 | 1ddb8431298 |
hex | 102d6ce61fd |
1111705412093 has 2 divisors, whose sum is σ = 1111705412094. Its totient is φ = 1111705412092.
The previous prime is 1111705412071. The next prime is 1111705412113. The reversal of 1111705412093 is 3902145071111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1069377287449 + 42328124644 = 1034107^2 + 205738^2 .
It is a cyclic number.
It is not a de Polignac number, because 1111705412093 - 222 = 1111701217789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111705412693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555852706046 + 555852706047.
It is an arithmetic number, because the mean of its divisors is an integer number (555852706047).
Almost surely, 21111705412093 is an apocalyptic number.
It is an amenable number.
1111705412093 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111705412093 is an equidigital number, since it uses as much as digits as its factorization.
1111705412093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 35.
The spelling of 1111705412093 in words is "one trillion, one hundred eleven billion, seven hundred five million, four hundred twelve thousand, ninety-three".
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