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11120002013 is a prime number
BaseRepresentation
bin10100101101100110…
…11100001111011101
31001200222020122001102
422112303130033131
5140233210031023
65035232122445
7542364312641
oct122663341735
931628218042
1011120002013
114796a5110a
1221a4096425
131082a52463
14776bcac21
15451395628
hex296cdc3dd

11120002013 has 2 divisors, whose sum is σ = 11120002014. Its totient is φ = 11120002012.

The previous prime is 11120002007. The next prime is 11120002031. The reversal of 11120002013 is 31020002111.

Together with next prime (11120002031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7110199684 + 4009802329 = 84322^2 + 63323^2 .

It is a cyclic number.

It is not a de Polignac number, because 11120002013 - 28 = 11120001757 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11120001985 and 11120002003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11120002213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560001006 + 5560001007.

It is an arithmetic number, because the mean of its divisors is an integer number (5560001007).

Almost surely, 211120002013 is an apocalyptic number.

It is an amenable number.

11120002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11120002013 is an equidigital number, since it uses as much as digits as its factorization.

11120002013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 11120002013 its reverse (31020002111), we get a palindrome (42140004124).

The spelling of 11120002013 in words is "eleven billion, one hundred twenty million, two thousand, thirteen".