Base | Representation |
---|---|
bin | 11001010010001100000111… |
… | …010100101011001100011101 |
3 | 112120201201112022211202001111 |
4 | 121102030013110223030131 |
5 | 104033404344001333203 |
6 | 1032301031221542021 |
7 | 32265005305554235 |
oct | 3122140724531435 |
9 | 476651468752044 |
10 | 111201121121053 |
11 | 32483148958107 |
12 | 1057b632574911 |
13 | 4a082b3c235b2 |
14 | 1d6623d304cc5 |
15 | ccc8e2a5726d |
hex | 65230752b31d |
111201121121053 has 2 divisors, whose sum is σ = 111201121121054. Its totient is φ = 111201121121052.
The previous prime is 111201121121003. The next prime is 111201121121089. The reversal of 111201121121053 is 350121121102111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106959177199449 + 4241943921604 = 10342107^2 + 2059598^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111201121121053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111201121121003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600560560526 + 55600560560527.
It is an arithmetic number, because the mean of its divisors is an integer number (55600560560527).
Almost surely, 2111201121121053 is an apocalyptic number.
It is an amenable number.
111201121121053 is a deficient number, since it is larger than the sum of its proper divisors (1).
111201121121053 is an equidigital number, since it uses as much as digits as its factorization.
111201121121053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 22.
Adding to 111201121121053 its reverse (350121121102111), we get a palindrome (461322242223164).
The spelling of 111201121121053 in words is "one hundred eleven trillion, two hundred one billion, one hundred twenty-one million, one hundred twenty-one thousand, fifty-three".
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