Base | Representation |
---|---|
bin | 11001010010001100001100… |
… | …000010000010010100001101 |
3 | 112120201201201211111100202012 |
4 | 121102030030002002110031 |
5 | 104033410024212333401 |
6 | 1032301043123111005 |
7 | 32265010255214126 |
oct | 3122141402022415 |
9 | 476651654440665 |
10 | 111201200121101 |
11 | 32483189506002 |
12 | 1057b654b12465 |
13 | 4a082c73c379c |
14 | 1d662499cb04d |
15 | ccc8e995e8bb |
hex | 65230c08250d |
111201200121101 has 2 divisors, whose sum is σ = 111201200121102. Its totient is φ = 111201200121100.
The previous prime is 111201200121071. The next prime is 111201200121119. The reversal of 111201200121101 is 101121002102111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59708089864201 + 51493110256900 = 7727101^2 + 7175870^2 .
It is a cyclic number.
It is not a de Polignac number, because 111201200121101 - 210 = 111201200120077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111201200121001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600600060550 + 55600600060551.
It is an arithmetic number, because the mean of its divisors is an integer number (55600600060551).
Almost surely, 2111201200121101 is an apocalyptic number.
It is an amenable number.
111201200121101 is a deficient number, since it is larger than the sum of its proper divisors (1).
111201200121101 is an equidigital number, since it uses as much as digits as its factorization.
111201200121101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 111201200121101 its reverse (101121002102111), we get a palindrome (212322202223212).
The spelling of 111201200121101 in words is "one hundred eleven trillion, two hundred one billion, two hundred million, one hundred twenty-one thousand, one hundred one".
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