Base | Representation |
---|---|
bin | 1010000111010001101011… |
… | …0111111110010001011011 |
3 | 1110101001222100220101121011 |
4 | 2201310122313332101123 |
5 | 2424143002012204242 |
6 | 35352302501554351 |
7 | 2225254653466441 |
oct | 241643267762133 |
9 | 43331870811534 |
10 | 11120121209947 |
11 | 35a8020581942 |
12 | 12b71a21159b7 |
13 | 628813769c89 |
14 | 2a6306a30b91 |
15 | 1443d7103d17 |
hex | a1d1adfe45b |
11120121209947 has 2 divisors, whose sum is σ = 11120121209948. Its totient is φ = 11120121209946.
The previous prime is 11120121209893. The next prime is 11120121210001. The reversal of 11120121209947 is 74990212102111.
It is a balanced prime because it is at equal distance from previous prime (11120121209893) and next prime (11120121210001).
It is a cyclic number.
It is not a de Polignac number, because 11120121209947 - 243 = 2324028187739 is a prime.
It is not a weakly prime, because it can be changed into another prime (11120124209947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560060604973 + 5560060604974.
It is an arithmetic number, because the mean of its divisors is an integer number (5560060604974).
Almost surely, 211120121209947 is an apocalyptic number.
11120121209947 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120121209947 is an equidigital number, since it uses as much as digits as its factorization.
11120121209947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 40.
The spelling of 11120121209947 in words is "eleven trillion, one hundred twenty billion, one hundred twenty-one million, two hundred nine thousand, nine hundred forty-seven".
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