Base | Representation |
---|---|
bin | 10000001011101001000… |
… | …101111010000001110101 |
3 | 10221022022001010212012212 |
4 | 100023221011322001311 |
5 | 121204400110431401 |
6 | 2210503520423205 |
7 | 143224461521633 |
oct | 20135105720165 |
9 | 3838261125185 |
10 | 1112012202101 |
11 | 399668997249 |
12 | 15b622777b05 |
13 | 80b29622a78 |
14 | 3bb70980353 |
15 | 1ddd5331dbb |
hex | 102e917a075 |
1112012202101 has 2 divisors, whose sum is σ = 1112012202102. Its totient is φ = 1112012202100.
The previous prime is 1112012202097. The next prime is 1112012202113. The reversal of 1112012202101 is 1012022102111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1105439857201 + 6572344900 = 1051399^2 + 81070^2 .
It is a cyclic number.
It is not a de Polignac number, because 1112012202101 - 22 = 1112012202097 is a prime.
It is a super-2 number, since 2×11120122021012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112012202131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556006101050 + 556006101051.
It is an arithmetic number, because the mean of its divisors is an integer number (556006101051).
Almost surely, 21112012202101 is an apocalyptic number.
It is an amenable number.
1112012202101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112012202101 is an equidigital number, since it uses as much as digits as its factorization.
1112012202101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 1112012202101 its reverse (1012022102111), we get a palindrome (2124034304212).
The spelling of 1112012202101 in words is "one trillion, one hundred twelve billion, twelve million, two hundred two thousand, one hundred one".
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