1112013013 has 2 divisors, whose sum is σ = 1112013014. Its totient is φ = 1112013012.

The previous prime is 1112012989. The next prime is 1112013031. The reversal of 1112013013 is 3103102111.

Together with next prime (1112013031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1066544964 + 45468049 = 32658^2 + 6743^2 .

It is a cyclic number.

It is not a de Polignac number, because 1112013013 - 2¹³ = 1112004821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1112012984 and 1112013002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1112013053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556006506 + 556006507.

It is an arithmetic number, because the mean of its divisors is an integer number (556006507).

Almost surely, 2^1112013013 is an apocalyptic number.

It is an amenable number.

1112013013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112013013 is an equidigital number, since it uses as much as digits as its factorization.

1112013013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1112013013 is about 33346.8591174641. The cubic root of 1112013013 is about 1036.0243347469.

Adding to 1112013013 its reverse (3103102111), we get a palindrome (4215115124).

The spelling of 1112013013 in words is "one billion, one hundred twelve million, thirteen thousand, thirteen".