Base | Representation |
---|---|
bin | 110011110010000011… |
… | …1010101110100001100 |
3 | 101122000210212221122120 |
4 | 1213210013111310030 |
5 | 3310220013441022 |
6 | 123030222012540 |
7 | 11014446361560 |
oct | 1474407256414 |
9 | 348023787576 |
10 | 111201312012 |
11 | 4318427265a |
12 | 19675117150 |
13 | a64236060b |
14 | 554c9756a0 |
15 | 2d5c7e1d5c |
hex | 19e41d5d0c |
111201312012 has 48 divisors (see below), whose sum is σ = 300598996992. Its totient is φ = 31336571520.
The previous prime is 111201312011. The next prime is 111201312017. The reversal of 111201312012 is 210213102111.
It is a junction number, because it is equal to n+sod(n) for n = 111201311982 and 111201312000.
It is not an unprimeable number, because it can be changed into a prime (111201312011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9061164 + ... + 9073427.
It is an arithmetic number, because the mean of its divisors is an integer number (6262479104).
Almost surely, 2111201312012 is an apocalyptic number.
111201312012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
111201312012 is an abundant number, since it is smaller than the sum of its proper divisors (189397684980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111201312012 is a wasteful number, since it uses less digits than its factorization.
111201312012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18134678 (or 18134676 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 111201312012 its reverse (210213102111), we get a palindrome (321414414123).
The spelling of 111201312012 in words is "one hundred eleven billion, two hundred one million, three hundred twelve thousand, twelve".
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