1112015011 has 2 divisors, whose sum is σ = 1112015012. Its totient is φ = 1112015010.

The previous prime is 1112014991. The next prime is 1112015027. The reversal of 1112015011 is 1105102111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1112015011 - 2⁵ = 1112014979 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1112014982 and 1112015000.

It is not a weakly prime, because it can be changed into another prime (1112015041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556007505 + 556007506.

It is an arithmetic number, because the mean of its divisors is an integer number (556007506).

Almost surely, 2^1112015011 is an apocalyptic number.

1112015011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112015011 is an equidigital number, since it uses as much as digits as its factorization.

1112015011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10, while the sum is 13.

The square root of 1112015011 is about 33346.8890752946. The cubic root of 1112015011 is about 1036.0249552358.

Adding to 1112015011 its reverse (1105102111), we get a palindrome (2217117122).

The spelling of 1112015011 in words is "one billion, one hundred twelve million, fifteen thousand, eleven".