Base | Representation |
---|---|
bin | 1010000111010001111110… |
… | …0100111010110101011011 |
3 | 1110101002011212100111001211 |
4 | 2201310133210322311123 |
5 | 2424143132211214321 |
6 | 35352314400523551 |
7 | 2225256632164225 |
oct | 241643744726533 |
9 | 43332155314054 |
10 | 11120200101211 |
11 | 35a8061066033 |
12 | 12b72046205b7 |
13 | 628826bcc7b6 |
14 | 2a63132c9415 |
15 | 1443dded90e1 |
hex | a1d1f93ad5b |
11120200101211 has 2 divisors, whose sum is σ = 11120200101212. Its totient is φ = 11120200101210.
The previous prime is 11120200101139. The next prime is 11120200101251. The reversal of 11120200101211 is 11210100202111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11120200101211 - 29 = 11120200100699 is a prime.
It is a super-3 number, since 3×111202001012113 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11120200101191 and 11120200101200.
It is not a weakly prime, because it can be changed into another prime (11120200101251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560100050605 + 5560100050606.
It is an arithmetic number, because the mean of its divisors is an integer number (5560100050606).
Almost surely, 211120200101211 is an apocalyptic number.
11120200101211 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120200101211 is an equidigital number, since it uses as much as digits as its factorization.
11120200101211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 11120200101211 its reverse (11210100202111), we get a palindrome (22330300303322).
The spelling of 11120200101211 in words is "eleven trillion, one hundred twenty billion, two hundred million, one hundred one thousand, two hundred eleven".
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